I need answer with reason please
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area of tube is inversely propotional to liquid velocity then R1=5cm V1=10m/s and R2 =4cm V2=? equation V1/V2=πR2^2/πR1^2 , 10/V2=4^2/5^2 , 10/V2=16/25,, V2=250/16... V2 is 15.625m/s ans
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