Question

i need answers for the problems in the image above,as soon as possible.

Answer 1

7. angle AOB =110°( since OP bisects the angle AOP)
8.angle NLO=angle NMO = 25°
angle NLO+angle NMO =angle LKM= 50°
OK bisects the angle LKM
Therefore Angle LKN =25°
9.In triangle ADB
angle A =50°
angle D = 60°( since angle D = angleC)
Therefore Angle ABD = 180 - angle A + angle D - ( sum of the angles in a triangle)
=180- 50+60
= 70°
plz mark as branliest answer.

Answer 2

Here's the solution to your question......