Question

I need correct answer​

Answer 1

Given, diameter,d= 0.5mm

resistivity,p =1.6×10-8m

Resistance,R =10m

let the length of wire be 1.

A=πd^2/4

R= P1 /A

= P1 /πd^2/4

= 1 = Rπd^2/4p

1 = 10× 3.14 ×[0.5×10^-3]2/4×1.6×10^-8

1= 122m

R prposnal 1/d^2

If the diameter is doubled,

resistance will be one_ fourth .

Answer 2

Answer:

d= 0.5mm

rho= 1.6 × 10^-8

R = 10mm

A= pid^2/4

R= rho l/A

After solving......

l= 122m

Dis doubled so R = 1/4