Question

i need full explaination please

Answer 1

Take mv' as the final momentum and mv as initial momentum.

And take the g as 10m/s

∆p = mv'-mv

∆p = 1x10 - 1x10

∆p = 0

So the change in momentum is “0”

Prompt me for sure If I am wrong.

Thanks For Reading.

Answer 2

Answer:

Explanation:

∆p = mv'-mv

∆p = 1x10 - 1x10

∆p = 0

So the change in momentum is “0”

d ) option