Question

I need full solution please give the right answer ​

Answer 1

★GIVEN★

$\large{\sf{27))\:({2}^{0}+{3}^{-1})\times{3}^{2}}}$

★SOLUTION★

$\large\implies{\sf{({2}^{0}+{3}^{-1})\times{3}^{2}}}$

$\large\implies{\sf{(1+\dfrac{1}{3})\times9}}$

$\large\implies{\sf{(\dfrac{3+1}{3})\times9}}$

$\large\implies{\sf{\dfrac{4}{3}\times9}}$

$\large\implies{\sf{\dfrac{4}{\cancel{3}}\times\cancel{9}}}$

$\large\therefore\boxed{\bf{27))\:12.}}$

★GIVEN★

$\large{\sf{28))\:{5}^{2x+1}\div25=125}}$

★To Find★

The value of x.

★SOLUTION★

$\large\implies{\sf{{5}^{2x+1}\div25=125}}$

We know that 5 × 5 = 25 and 5 × 5 × 5 = 125.

So,

$\large\implies{\sf{{5}^{2x+1}\div{5}^{2}={5}^{3}}}$

Comparing the bases,

$\large\implies{\sf{2x+1-2=3}}$

$\large\implies{\sf{2x-1=3}}$

$\large\implies{\sf{2x=3+1}}$

$\large\implies{\sf{2x=4}}$

$\large\implies{\sf{x=\dfrac{4}{2}}}$

$\large\implies{\sf{x=\dfrac{\cancel{4}}{\cancel{2}}}}$

$\large\therefore\boxed{\bf{28))\:x=2}}$

1)) Answer of 27)) is 12.

2)) Answer of 28)) is 2.