Question

I need help ASAP! here's the question! Look at the figure below: Triangle ABC has the measure of angle ACB equal to 45 degrees. D is a point on side AC. Points B and D are joined by a straight Make a two-column proof showing statements and reasons to prove that triangle ABD is similar to triangle ACB.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given:

Angle ABD = 45°

Angle ACB = 45°

To Find:

Prove that triangle ABD is similar to triangle ACB.

Solution:

Two triangles are similar if they satisfy one of the following criteria.

AA: Two pairs of corresponding angles are equal.

SSS: Three pairs of corresponding sides are proportional.

SAS: Two pairs of corresponding sides are proportional and the corresponding angles between them are equal.

According to the question,

∠ABD = ∠ACB = (45°)

∠BAD = ∠BCD  (Common)

Now, since two pairs of corresponding angles are equal.

Therefore, ΔABD is similar to ΔACB by the property of 'AA'.

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