Question

i need help for this one

Answer 1

Answer:

For the first system

$\frac{a1}{a2} = \frac{5}{20} = \frac{1}{4} \\ \frac{b1}{b2} = \frac{1}{4} \\ \frac{c1}{c2} = \frac{13}{64} \\ so \: it \: means$

system of equations has no solution.

For second system

equations are

5x + y = 13

20x + 4y = 52

$\frac{a1}{a2} = \frac{5}{20} = \frac{1}{4} \\ \frac{b1}{b2} = \frac{1}{4} \\ \frac{c1}{c2} = \frac{13}{52} = \frac{1}{4} \\ it \: means$

System has infinitely many solutions.

Answer 2

Answer:

this is correct...............