Question

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Please solve..​

Answer 1

Answer:

1- c

Step-by-step explanation:

If alpha and Beta are the zeroes  of the polynomial  x^2-p(x+1)-c,  find the value of (alpha +1)(beta+1)

 

x2 - p(x + 1) - c 

= x2 - px - p - c 

 

Comparing with ax2 + bx + c, we get

 a= 1 , b = -p and c = - p - c

 

α and β are the zeroes of the given polynomial.

 

→ α + β = -b/a = -(-p)/1 = p

and αβ = c/a = -p - c / 1 = -p - c

 

To find: (α + 1)(β + 1) 

(α + 1)(β + 1) = αβ + α + β + 1

                      = - p - c + p + 1 

                      = 1 - c

Answer 2

Answer:

1-C is the correct answer