Question

i need help
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Answer 1

$</p><p>\sf \rightarrow \quad \dfrac{tan \: \theta \cdot \sqrt{1 - {sin}^{2} \: \theta } }{ \sqrt{1 - {cos}^{2} \: \theta } } \\ \\ \sf \rightarrow \quad \dfrac{tan \: \theta \cdot \sqrt{ {cos}^{2} \: \theta} }{ \sqrt{ {sin}^{2} \: \theta} } \\ \\ \sf \quad \because \: {sin}^{2} \: \theta + {cos}^{2} \: \theta = 1 \\ \\ \sf \rightarrow \quad tan \: \theta \cdot \frac{ cos \: \theta}{sin \: \theta} \\ \\ \sf \rightarrow \quad \cancel{tan \: \theta} \cdot \frac{1}{ \cancel{tan \: \theta}} \\ \\ \sf \rightarrow \quad 1</p><p>$