Question

I need help on Lesson 2: Semester B Exam CE 2015
Algebra 2 B Unit 8: Semester B Review and Exam
here are the first 2 questions there are 47 questions

Answer 1

Answer:

(1) A

(2) B

Step-by-step explanation:

i hope this helps u

Answer 2

Concept

In elementary algebra, the procedure of rationalization is performed to get rid of the irrational number in the denominator. To rationalize the denominator, a variety of strategies are available. Making something more effective is the exact meaning of the term rationalize.

Given

One radical expression and one non rationalized fraction is given.

Find

Simpler form of the radical expression and rationalizing the denominator.

Solution

$1)$ $\sqrt[4]{2401*x^{12}y^{16} } =\sqrt[4]{7^{4}x^{4*3}x^{4*4} } =7x^{3} y^{4}$

Therefore, simpler form of the radical expression is $7x^{3} y^{4}$.

$2)$ $\frac{\sqrt[3]{2} }{\sqrt[3]{4} } =\frac{\sqrt[3]{2}*\sqrt[3]{2} }{\sqrt[3]{4}*\sqrt[3]{2} }$ $= \frac{\sqrt[3]{4} }{\sqrt[3]{8} } =\frac{\sqrt[3]{4} }{2 }$

Hence, simpler form of radical expression $\sqrt[4]{2401*x^{12}y^{16} }$ is  $7x^{3} y^{4}$ and after rationalizing the denominator of the given equation we get $\frac{\sqrt[3]{4} }{2 }$.

#SPJ2