Question

I need help on Lesson 2: Semester B Exam CE 2015
Algebra 2 B Unit 8: Semester B Review and Exam

Answer 1

Answer:

I dont no answer to your question so like me

I don't know how to do your question

Answer 2

Answer:

Option D

Step-by-step explanation:

Given:-

f(x) = x^2+6

g(x) = (x+8)/x

To find:-

Find gof(-7) ?

Solution:-

Given that

f(x) = x^2+6

g(x) = (x+8)/x

We know that

g o f(x)

=> g(f(x))

=>g o f means f(x) function is in g(x) function

=> [(x^2+6)+8)]/(x^2+6)

=> (x^2+6+8)/(x^2+6)

=> (x^2+14)/(x^2+6)

g o f (x) = (x^2+14)/(x^2+6)

Now ,

g o f (-7)

=> g(f(-7))

=> [(-7)^2+14]/[(-7)^2+6]

=> (49+14)/(49+6)

=> 63/55

Answer:-

The value of g o f (-7) for the given problem is 63/55

Used formulae:-

• g o f(x) = g(f(x))

• g o f means f(x) function is in g(x) function.