Question

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Answer 1

The given equations are:  5/x + 6y = 13 ……..(i) 

3/x + 4y = 7 ……..(ii) 

Putting 1/x = u, we get: 5u + 6y = 13 …….(iii) 

3u + 4y = 7 ……(iv) 

On multiplying (iii) by 4 and (iv) by 6, we get:  20u + 24y = 52 ……..(v)  18u + 24y = 42 ……..(vi) 

On subtracting (vi) from (v), we get:  2u = 10 ⇒ u = 5  ⇒ 1/x = 5  ⇒ x = 1/5 

On substituting x = 1/5 in (i),

we get:  5/ 1/3 ⁄ + 6y = 13  25 + 6y = 13  6y = (13 – 25) = -12  y = -2 

Hence, the required solution is x = 1/5 and y = -2

Answer 2

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