Question

i need help!!!


Please Solve Guyzzz​

Answer 1

Answer:

60 cm2

Step-by-step explanation:

the area of quadrilateral is 1/2×2×5×12

=60cm2

Answer 2

Answer:

60 cm²

Step-by-step explanation:

Correct option is

A

60 cm2

The radius perpendicular tangent at the pt. of contact, therefore, OQ⊥PQ and OR⊥PR

In rt. △OPQ, we have

PQ=OP2−OQ2

   =169−25=144=12 cm

⇒ PR=12 cm (Two tangents from the same external pt. to a circle are equal)

Now area of quad. PQOR=2×Area of △POQ

   =(2×21×12×5) cm2=60 cm²

Hope this will help you

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