Question

I need help someone just explain how to solve these please

The Pythagorean Triple Threat is a coed softball team. League rules require the batting order to alternate boy-girl-boy-girl… (or girl-boy-girl-boy…). If there are five girls and five boys on the team, how many different batting orders are possible?

Eight boys and seven girls showed up to one of the team’s games. League rules limit each team to 10 players at a time (five girls and five boys) per game. Given this rule, how many combinations of 10 players are there among the 15 boys and girls who showed up at this particular game?

At a different game, four boys and six girls showed up. Even though only four boys showed up, they had a total of ten players, so the team could play, provided they followed batting order rule. In order to keep the required alternating pattern in the batting order, each boy will bat more often than each girl. Representing the six girls with A, E, I, O, U and Y and the four boys with J, K, L and M, the coach decides to following this batting order: A, J, E, K, I, L, O, M, U, J, Y, K, A, L, E, M…. According to this line-up, J is next to bat following A. How many total times will E bat before the next time that J is next to bat following A?

Answer 1

It is H x H=b2 +c2

it is The proposal is to the Pythagorean triplets