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20)let the age of the son be x them the age of the father is 30+x and by the question , x+29=4x-4
or 3x=33,or x=11 years.then father's and son's present age=41and 11.
23)now the lateral surface area of the roller=2πrh=132×2cm².then in 1 revolution=132×2cm² then in 600revolutions =2217600cm².so the area of the play ground=2217600cm².so the cost is 221.76×8.50=1884.96.
25)consider the SP of second cow as x. then SP of the first cow=115/100×20,000=23,000.
so total CP - total SP=1800
or,17000-x=1800,or x=15200. hence the selling price of the second cow=15200.
or 3x=33,or x=11 years.then father's and son's present age=41and 11.
23)now the lateral surface area of the roller=2πrh=132×2cm².then in 1 revolution=132×2cm² then in 600revolutions =2217600cm².so the area of the play ground=2217600cm².so the cost is 221.76×8.50=1884.96.
25)consider the SP of second cow as x. then SP of the first cow=115/100×20,000=23,000.
so total CP - total SP=1800
or,17000-x=1800,or x=15200. hence the selling price of the second cow=15200.
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