I need help with phytagoras theorem
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Using Pythagoras theorem,
8 square+(x-1)square=(x+3)square
64+x^2+1-x=x^2+9+6x
65-9=6x+x
56=7x
x=8
8 square+(x-1)square=(x+3)square
64+x^2+1-x=x^2+9+6x
65-9=6x+x
56=7x
x=8
shaki2:
where do you get 64from
squaring 8
use the whole square formula to simplify (x-1)^2 & (x+3)^2
Answered by
3
According to Pythagoras Theorem ,
Side² + Side² = Hypotenuse ²
The sides which make 90° are not Hypotenuse!
according to Pythagoras Theorem ,
We can simplify your question as,
(x-1)²+ 8² = (x+3)²
x²+1-2x + 64 = x²+9+6x
65-9 = 8x
56 = 8x,
x = 7,
Hypotenuse = 7+3 = 10,
The other side = 7-1 = 6 !
Side² + Side² = Hypotenuse ²
The sides which make 90° are not Hypotenuse!
according to Pythagoras Theorem ,
We can simplify your question as,
(x-1)²+ 8² = (x+3)²
x²+1-2x + 64 = x²+9+6x
65-9 = 8x
56 = 8x,
x = 7,
Hypotenuse = 7+3 = 10,
The other side = 7-1 = 6 !
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