Question

I need help with Q's tagged below

Answer 1

Answer:

3x²+(x-1)(x+1)+3(x+2)+5 at x=-1

Step-by-step explanation:

3x²+x²-(1)²+3(x+2)+5 [using the identity (a-b)(a+b)=a²-b² at (x-1)(x+1)]

3x²+x²-1+3x+6+5 [opening the bracket 3(x+2)]

4x²+3x+10 [ as 6+5-1=10]

substitute the value of x=-1

4(-1)²+3(-1)+10

4(1)-3+10

4-3+10

11

Therefore the ans is 11