I need help with some expansion and simplification of linear expressions :
6k-2(1-k)+3
2(-x-y) - 2x-y)
2e+3f-2(e-f)
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1
Answer:
The two equations can be written as
x2 (6k+2) + rx +(3k-1) = 0 ...(1)
and x2 {12k + 4) + px + (6k - 2) = 0. ...(2)
Divide by 2
∴ x2 (6k+2)+2px + {3k-1)=0 ...(3)
Comparing (1) and (3), we get r = 2p ∴ 2r-p = 0.
afrakh017:
ty
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