I need help with the 8th question guys..
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as in ∆ OAP and ∆OBQ
angle aop = angle qob(vertically opposite angles)
PA=QB
angle PAO = angle QBO = each 90°
so from AAS property
∆OAP =~ ∆OBQ
so OA = OB
angle aop = angle qob(vertically opposite angles)
PA=QB
angle PAO = angle QBO = each 90°
so from AAS property
∆OAP =~ ∆OBQ
so OA = OB
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