i need java program answer of this . (use if - else)
what i did:
import java.util.*;
class electronics
{
Scanner sc=new Scanner(System.in);
public void main()
{ int pa;
float dis,ap;
System.out.println("Enter the purchased amount");
pa=sc.nextInt();
if(pa>=20000)
{
dis=pa/20000*25;
ap=pa-dis;
System.out.println("Discount of "+dis);
System.out.println("the amount payable will be"+ap);
System.out.println("Gift of an Ipod");
}
else if((pa =15000))
{
dis=pa/20000*20; //discount calculation
ap=pa-dis; // amount payable calculation
System.out.println("discount of"+dis);
System.out.println("the amount payable will be"+ap);
System.out.println("gift of a wrist watch");
}
else if(pa =12000)
{
dis=pa/20000*16; //discount calculation
ap=pa-dis; // amount payable calculation
System.out.println("discount of "+dis);
System.out.println("the amount payable will be"+ap);
System.out.println("gift of a wall clock");
}
else if(pa =5000)
{
dis=pa/20000*11; //discount calculation
ap=pa-dis; // amount payable calculation
System.out.println("Discount of "+dis);
System.out.println("the amount payable will be"+ap);
System.out.println("gift of a digital table clock");
}
else
{
dis=pa/20000*5; //discount calculation
ap=pa-dis; // amount payable calculation
System.out.println("discount of "+dis);
System.out.println("the amount payable will be"+ap);
System.out.println("gift of a pen set");
}
}
}
HELP ME WITH IT...
Answers
Answer:
Surface Area of Cuboid is =
2(lb + lh + bh)
By surface area of a cuboid we mean the total surface area.
The sum of the areas of 4 vertical faces of a cuboid is called its lateral surface area.
The lateral surface area or the area of the four walls of the cuboid .
Area of the four walls = 2 (l +b) h
==========================================================
Solution:
Given;
Length of wall (l)= 15 m, Breadth of wall (b)= 10 m Height of wall (h) = 7 m
Total area to be painted= area of 4 walls + area of ceiling
= 2(l+b)h + lb
= 2(15+10)7 + 15×10
= 2×25×7+ 150
=50× 7+150= 350+ 150=500
Total area to be painted=500m²
Given 100m² area can be painted from each can.
Number of cans Required=
Area of hall/ area of 1 can
= 500/100= 5
Hence, 5 cans are required to paint the room.
==========================================================
Hope this will help you...
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Answer
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litikaswani
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cans
You have to use the open cuboid formula
=2h(l+b) +lb
=2*7(15+10)+ (15)(10)
=14*25+150
=490
No. of cans required = 490/100
= 4.90 cans
rosariomividaa3 and 103 more users found this answer helpful
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49
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(54 votes)
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