Question

I need only correct answer fully solved​

Answer 1

Answer:

pQ=pR(given)

ps =pQ(given)

In triangle pQR and triangle RQS

PQ= PR(Given)

PS =PQ(given)

QR=RQ(common)

bySSS Triangle pQR CONGRUENCE RQS..

angle PQR= RQS ( BY CPCT)

BY ANGLE SUM PROPERTY OF TRIANGLE..

angle PQR +angle RQS = 180 DEGREE

angle pQR = angle RQS ( above proved)

So;

angle RQS +angle RQS= 180 DEGREE

2 RQS = 180 DEGREE

RQS = 180/2

.. . RQS = 90 DEGREEE......

Answer is fully correct.

Answer 2

Answer:

by corresponding angles wecan prove that

Step-by-step explanation:

Given : pq=pr

ps=pq

to show :∆QRS is right angle

answer : (pq =pr

ps=pq) given

pq =pr=ps

p is the mid point of QS

let M be the mid point of QR

then,∆QMP is right angle triangle

(pq=pr , QR=MR , PM is common)

QR square + PM square=PQ square

P is the mid point of QS

therefore ∆QMP ~∆QRS

so ∆QMP IS THE RIGHT ANGLE TRIANGLE so ∆QRS will be the RIGHT ANGLE TRIANGLE

In similar ∆QRS IS CORRESPONDING ANGLE IS EQUAL

HENCE PROVED THAT

( ∆QRS IS THE RIGHT ANGLE TRIANGLE)