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in triangle ABD,
AD = BD ,
SO ,angle DAB = angle DBA.------(i)
again in triangle DBC ,
BD = CD,
SO, angle DBC = angle DCB--------(ii)
Now ,in triangle ABC ,
angle A+angle B+angle C = 180°
DAB +ABD +DBC +BCD = 180
2DBA +2DBC = 180
2(DBA +DBC ) = 180
SO,angle ABC = 90°.
AD = BD ,
SO ,angle DAB = angle DBA.------(i)
again in triangle DBC ,
BD = CD,
SO, angle DBC = angle DCB--------(ii)
Now ,in triangle ABC ,
angle A+angle B+angle C = 180°
DAB +ABD +DBC +BCD = 180
2DBA +2DBC = 180
2(DBA +DBC ) = 180
SO,angle ABC = 90°.
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