Question

I need solution for this​

Answer 1

Y= (A^x B^y)/C^z

taking log

logY= log{(A^x B^y)/C^}

=log(A^x B^y)- log C^z

= (logA^x+logB^y)-z logC

=xlog A +ylog B -z log C

differentiate both side,

dY/Y= x.dA/A + y.dB/B - z.dC/C

maximum percentage error,

dY/Y × 100 % = ( X.dA/A + y.dB/B + z.dC/C)× 100%

or,. =( xA + yB + zC)%

ans- (a)