Question

I need solution for this question

Answer 1

Dimension of B=that of v=L(T)^-1

Dimension of U=M L^2 T^-2

Dimension of U=that of Av^3/v+B

thus M L^2 T^-2=[A]* L^3 T^-3/L T^-1

[A]=M L^0

[A/B]=M/ L  T^-1=M L^-1 T =option 1)