Question

I need solution of this both questions​

Answer 1

Integration

2)

let tan inverse x be y

then dx = dy (1+ x²)

∫sin(2y) dy

=(- cos 2x)/2+c

1)

∫sec³x tanx dx

let secx = y

then , dy = secx tanx dx

∫sec²x secx tanx dx

= ∫y ² sec x tanx(dy/secx tanx )

= ∫y ²dy

= y³/3

=(sec³x /3 )+c

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