Question

i need solution please

Answer 1

TRS=TQR+QTR

QTR=TRS-TQR--------------------(1)

In triangle PQR

PRS=PQR+PQR. {exterior angle equals to sum of two interior angles}

RT bisects PRS

TRS=1/2 PRS

QT bisects PQR

TQR=1/2PQR

substituting(1)

QTR=TRS-TQR

QTR=1/2PRS-1/2PQR

QTR=1/2(PRS-PQP)--------------------(2)

In triangle PQR

PRS=PQR+PQR

substituting in(2)

QTR=1/2(PQR+QPR-PQR)

PQR=1/2QPR