Question

i need step by step explanation of the the question in the pic attached

answer of question no. 6

Answer 1

Answer

(x+y-8)/2= (x+2y-14)/3 = (3x+y-12)/11

(x+y-8)/2……….(1)

(x+2y-14)/3………(2)

(3x+y-12)/11……..(3)

Take eq 1& 2

(x+y-8)/2= (x+2y-14)/3

3(x+y-8)= 2(x+2y-14)

3x+3y-24= 2x+4y-28

3x-2x+3y-4y= -28+24

x-y= -4

x-y+4=0…………….(3)

Take eq 2 & 3

(x+2y-14)/3 = (3x+y-12)/11

11 (x+2y-14)= 3(3x+y-12)

11x+22y - 154= 9x+3y-36

11x -9x+22y-3y= -36+154

2x+19y= 118

2x+19y-118=0…………….(4)

Multiply equation (3) by 2  

2x-2y+8=0………..(5)

subtract equation (4) from eq (5)

2x-2y+8=0

2x+19y-11

☺-21y+126=0

☺-21y=-126

☺y= 126/21= 6

☺y= 6

☺From eq 3

☺x+y -8=0

☺x+6-8=0

☺x-2=0

☺x=2

☺Hence, the value of x= 2 & y= 6

hope this helps you

Answer 2

$\large{\frac{x+y-8}{2} = \large{\frac{x+2y-14}{3}$

$\large{2x+4y-28 = 3x+3y-24$

$\large\black\boxed{{-x+y = 4}}.....(i)$

$\large{\frac{x+2y-14}{3}} = \large{\frac{3x+y-12}{11}}$

$\large{11x+22y-154 = 9x+3y-36}$

$\large\black\boxed{2x+19y = 118}.....(ii)$

Equation (i)×2

$(i)*2\rightarrow \large\black\boxed{-2x+2y = 8}.....(iii)$

Equation (ii)+(iii)

$21y = 126$

$\large\black\boxed{y = 6}$

Substitute y = 6 in equation (i)

$-x+6 = 4$

$\large\black\boxed{x=2}$