Math, asked by Keshav661, 2 months ago

I need step by step explanations :-:​

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Answered by jatsv243
2

Answer:

Saurabh can finish a work in 18 hours, while Vinod can finish it in 24 hours. How long will it take them to finish the work together if Saurabh is called away 2 hours before the completion of the work, while Vinod continued with the work?

Let the total work be 72 units(L.C.M of 18,24 taken for calculation purposes).

Vinod does 4 units of work per hour. Saurabh does 3 units per hour.

Let 't' be the number of hours taken to complete the work.

Vinod completed 4t units of work and Saurabh completed 3(t-2) units of work.

We took 72 units as the total work. So,

4t + 3t - 6 = 72

7t = 78

t = 78/7=11.14 hours.

Hari and Ravi can finish a work in 18 days. How many days would Ravi will finish the work alone if Hari can finish this work in 24 days alone?

Ravi can do three fourth of a work in hours while Hira can do two third of the same work in 8 hours. If both started working together then in how much time the work will be completed?

If I can do 3/4 of a work in 18 days, in how many days can I finish 1/4 of the work?

How long would it take to finish an artwork if you work 24 hours on it?

Can we work continuously for 24 hours without any break?

Saurabh in 1 hour = 1/18 of the work

Vinod in 1 hour = 1/24

Together in 1 hour = 1/18+1/24 = 7/72

Together they will take 72/7 hours

So they work together for 72/7 -2 = 58/7 hours

in this time they finish 58/7 x 7/72 = 58/72 = 29/36 of the work

So Vinod does 7/36 of the work in 7/36 x 24 = 14/3 hours

Total time = 58/7+ 14/3= ( 174 + 98) /21 = 272/21 = 12.95 hours ANSWER

Answered by shashankkumar8982
0

Answer:

saurav work=18-2=16hour

vinod=24hour

1hr=1/24+1/16=5/48

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