I NEED STEP WISE EXPLAINATION......
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Answer:
★Given: In a triangle ABC,
★D is a point on side BC such that AD = AC,
★We have to prove that : AB > AD
Proof:
★Since, AD = AC,
⇒ angle∠ACD = ∠ ADC
Since, ∠ADC is an exterior angle of triangle ABD,
⇒ ∠ADC = ∠ABD + ∠ BAD
⇒ ∠ADC > ∠ ABD
⇒ ∠ ACD > ∠ ABD
⇒ AB > AD
hence proved
hope it helps........★
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Answer:
Given:AD=AC
Angles opposite to equal sides are equal
So, ∠ACD=∠ADC .......(1)
Now, ∠ADC is an exterior angle of △ABD
∠ADC=∠ABD+∠BAD since exterior angle is sum of interior opposite angles.
So, ∠ADC>∠ABD
⇒∠ACD>∠ABD since side opposite to the greater angle is longer
∴AB>AD as AC=AD given
Hence proved.
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