Question

I need the answer fast please​

Answer 1

Step-by-step explanation:

the answer is 0 for the given question

Answer 2

Given:

4 tan A = 1

tan A = 1/4

Perpendicular / Base = k / 4k

Imagine of a right angled triangle having perpendicular of k length, base of 4k length.

So , By Pythagoras theorem

Hypotenuse² = Perpendicular ² + Base²

Hypotenuse² = (k)² + (4k)²

Hypotenuse² = k² + 16k²

Hypotenuse = √17k²

Hypotenuse = √17 k

So we have ,

Sin A = Perpendicular / Hypotenuse

=> sin A = k / √17 k

=> sin A = 1/√17

Cos A = Base / Hypotenuse

=> cos A = 4k/√17k

=> cos A = 4/√17

Putting value of sin A and cos A in the given question.

$</p><p></p><p>\rightarrow \quad \frac{ 4 \sin A - \cos A }{ 4 \sin A + \cos A } \\ \\</p><p></p><p>\rightarrow \quad \frac{ 4 \times \frac{1}{\sqrt{17}} - \frac{4}{\sqrt{17}} }{ 4 \times \frac{1}{\sqrt{17}} + \frac{4}{\sqrt{17}} } \\ \\</p><p></p><p></p><p>\rightarrow \quad \frac{ \frac{4}{\sqrt{17}} - \frac{4}{\sqrt{17}} }{ \frac{4}{\sqrt{17}} + \frac{4}{\sqrt{17}} } \\ \\</p><p></p><p>\rightarrow \quad \frac{0}{ \frac{8}{\sqrt{17}} } \\ \\</p><p></p><p>\longrightarrow \quad 0 </p><p></p><p>$

Answer : 0