Question

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Answer 1

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Answer 2

Answer:

Step-by-step explanation:

Sin+cos=√3

Tan+cot=1----0

Using the identify sin^2+cos^2=1---1

now we know that (sin+cos)^2=sin^2+cos^2+2sincos

So sin^2+cos^2 from above would be

As follow sin^2+cos^2=(sin+cos)^2-2sincos--2

Now using2in1

(sin+cos)^2-2sincos=1

3-2sincos=1

Sin cos=1

Sin=1÷cos----3

Now using 3in0

tan+cot=1

Sin÷cos+cos÷sin=1

Putting the value of 3in above equation we get

1/cos×1/cos+cos/1×cos/1=1

1/cos^2+cos^2=1

We know that 1/cos=sec

So sec^2+cos^2=1

Using the identify 1+tan^2=sec^2

1+tan^2+cos^2=1

1+sin^2/cos^2+cos^2=1

Sin^/cos^2+cos^2=1

Sin^2+cos^4/cos^2=1

Sin^2+cos^2=1

1=1 hence proved

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