Math, asked by BRAINLYY, 1 year ago

I need the answer of 16 ques

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Answered by jing
1
log identities used

log(ab) = log a + log b

log(a/b) = log a - log b

log(an ) = n log a

-

log(10x/y2) = log(10x) - log(y2 )

log(10x/y2) = log(10) + log(x) - 2log(y)

log(10x/y2) = 1 + log(x) - 2log(y)

log(10x/y2) = 1 + m + n - 2(m - n) = 1 + m + n - 2m + 2n

log(10x/y2) = 1 - m + 3n

Hope this help you....

jing: Welcome. Please mark it as rainliest...
jing: Welcome. Please mark it as rainliest...
jing: Brainliet
Answered by zyrilledhanielle18
0

Answer:

log identities used

log(ab) = log a + log b

log(a/b) = log a - log b

log(an ) = n log a

-

log(10x/y2) = log(10x) - log(y2 )

log(10x/y2) = log(10) + log(x) - 2log(y)

log(10x/y2) = 1 + log(x) - 2log(y)

log(10x/y2) = 1 + m + n - 2(m - n) = 1 + m + n - 2m + 2n

log(10x/y2) = 1 - m + 3n

Step-by-step explanation:

correct me if im wrong

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