I need the answer to question 3 with working
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x-5. x-3
----- X ----
x-3. x-2
----- X ----
x-3. x-2
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given that ∆AOB~∆DOC
OB/OC=OA/OD
OB.OD=OA.OC
x²-2x+3x-6 = x²-3x+5x-15
x = 2x-15+6
x. = 9
OB/OC=OA/OD
OB.OD=OA.OC
x²-2x+3x-6 = x²-3x+5x-15
x = 2x-15+6
x. = 9
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