Question

I need the answer to question 4 regarding intro to trigonometry class 10

Answer 1

sinA=√3-1

sin^2A+1/sinA

=(√3-1)^2+1/√3-1

=3+1-2√3+1/√3-1

=5-2√3/√3-1

Rationalizing,,,

=(5-2√3) (√3+1) /(√3-1) (√3+1)

=5√3+5-6-2√3/3-1

=3√3-1/2...

Pls mark as brainliest

Answer 2

sinA=√3-1

(sin^2A+1)/sinA

sinA+cosecA

sinA=1/cosecA

cosecA=1/sinA

than put the value sinA

√3-1 +1/(√3-1)

((√3-1)^2+1)/(√3-1)

after solving

(5-2√3) /(√3-1)

now rationalizations

(5-2√3) (√3+1) /(√3-1) (√3+1)

(5√3+5-6-2√3) /(3-1)

(3√3-1) /2

that's prove