Question

I need the answer to the question below with an explanation

Answer 1

Answer:

idc bro

Step-by-step explanation:

Answer 2

Answer:

a,b are the roots of the equation x^2+x+1=0

therefore

a+b = -1

ab=1

now for the equation x^2+px+q=0

a/b ,b/a are the roots

thus,

-p= sum of roots

-p= a/b+b/a

-p= a^2+b^2/ab

-p={(a+b)^2-2ab}/ab

by substituting the values

-p= 1-2/1

p=1

HOPE THIS WILL HELP YOU