I need the answers to these two questions.... thanks in advance
Attachments:
Answers
Answered by
2
1) An=n^3-6n^2+11n-6
So,for n=1
An=1^3-6(1)^2+11-6
An=1-6+11-6=0
Now n=2
An=2^3-6(2)^2+11(2)-6
An=8-24+22-6=0
Now n=3
An=3^3-6(3)^2+11(3)-6
An=27-54+33-6=0
Now n=4
An=4^3-6(4)^2+11(4)-6
An=64-96+44-6=6
So, all remaining will be positive
2) An=n(n-3)/(n-4)
n=18
An=18×15/14
An=19.3(approx)
PLZ MARK IT AS BRAINLIEST.
So,for n=1
An=1^3-6(1)^2+11-6
An=1-6+11-6=0
Now n=2
An=2^3-6(2)^2+11(2)-6
An=8-24+22-6=0
Now n=3
An=3^3-6(3)^2+11(3)-6
An=27-54+33-6=0
Now n=4
An=4^3-6(4)^2+11(4)-6
An=64-96+44-6=6
So, all remaining will be positive
2) An=n(n-3)/(n-4)
n=18
An=18×15/14
An=19.3(approx)
PLZ MARK IT AS BRAINLIEST.
Similar questions