Math, asked by shriyathakur42356, 4 months ago

I need the correct answer please answer it correctly. and fast.....

the volume of a rectangular box where area of adjacent faces are 50cm², 30cm² and 20cm² is?​

Answers

Answered by manav3010
18

Answer

50*(sqrt(12))

Step-by-step explanation:

x*y = 50

y*z = 30

z*x = 20

so

on solving we get

x = 10/sqrt{3} y = 5*sqrt{3}) z = sqrt{12}

hence volume = x*y*z

so x*y = 50

z = sqrt{12}

so v = 50*sqrt{12}

PLEASE MARK IT AS BRAINLIEST

Answered by Cynefin
40

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GiveN:

  • Area of adjacent faces are 50cm², 30cm² and 20cm².

To FinD:

  • Volume of the rectangular box?

Step-by-Step Explanation:

Let the length, breadth and the height of the cuboid be l, b and h.

Area of adjacent faces in terms of l,b and h

  • Area of faces with sides l and b = lb
  • Area of faces with sides b and h = bh
  • Area of faces with sides l and h = lh

Now multiplying lb, bh, and lh

= lb × bh × hl

= l²b²h²

= (lbh)²

We know lbh = V (Volume of the cuboid). Then,

⇒ (lbh)² = V²

⇒ lb × bh × hl = V²

Now plugging the given values of lb, bh and hl in the above equation,

⇒ V² = 50 cm² × 30 cm² × 20 cm²

⇒ V² = 30000 cm⁶

⇒ V = √30000 cm⁶

⇒ V = 173.21 cm³

Hence,

  • The required volume of the cuboid will be 173.21 cm³ (Ans)

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