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the volume of a rectangular box where area of adjacent faces are 50cm², 30cm² and 20cm² is?
Answers
Answered by
18
Answer
50*(sqrt(12))
Step-by-step explanation:
x*y = 50
y*z = 30
z*x = 20
so
on solving we get
x = 10/sqrt{3} y = 5*sqrt{3}) z = sqrt{12}
hence volume = x*y*z
so x*y = 50
z = sqrt{12}
so v = 50*sqrt{12}
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Answered by
40
GiveN:
- Area of adjacent faces are 50cm², 30cm² and 20cm².
To FinD:
- Volume of the rectangular box?
Step-by-Step Explanation:
Let the length, breadth and the height of the cuboid be l, b and h.
Area of adjacent faces in terms of l,b and h
- Area of faces with sides l and b = lb
- Area of faces with sides b and h = bh
- Area of faces with sides l and h = lh
Now multiplying lb, bh, and lh
= lb × bh × hl
= l²b²h²
= (lbh)²
We know lbh = V (Volume of the cuboid). Then,
⇒ (lbh)² = V²
⇒ lb × bh × hl = V²
Now plugging the given values of lb, bh and hl in the above equation,
⇒ V² = 50 cm² × 30 cm² × 20 cm²
⇒ V² = 30000 cm⁶
⇒ V = √30000 cm⁶
⇒ V = 173.21 cm³
Hence,
- The required volume of the cuboid will be 173.21 cm³ (Ans)
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