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if a^2+ b ^2 = 0
that means a = 0
b = 0
so 2x -4 = 0
X= 2
12-4y = 0
y = 3
thus x^y +y^x = 2^3+3^2 = 8+9 = 17
that means a = 0
b = 0
so 2x -4 = 0
X= 2
12-4y = 0
y = 3
thus x^y +y^x = 2^3+3^2 = 8+9 = 17
Anonymous:
ur wlcm
Answered by
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We know that if the sum of two non-negative numbers are zero, then each number should be zero.
Since square of any quantity is non-negative,
(2x - 4)^2 = 0 & (12 - 4y)^2 = 0
Thus,
(2x - 4) = 0 & (12 - 4y) = 0
Therefore x = 2 & y = 3.
Thus, x^y + y^x = 2^3 + 3^2 = 8 + 9 = 17.
Option: (c)
Since square of any quantity is non-negative,
(2x - 4)^2 = 0 & (12 - 4y)^2 = 0
Thus,
(2x - 4) = 0 & (12 - 4y) = 0
Therefore x = 2 & y = 3.
Thus, x^y + y^x = 2^3 + 3^2 = 8 + 9 = 17.
Option: (c)
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