I need the solution to this urgently please.
Answers
As We know that cos A = ⅗.
→ cos A = B/H
→ Cos A = ⅗
By Using Pythagoras theorem, we can find the Perpendicular of the traingle using h² = b² + p² Formula.
→ 5² = 3² + p²
→ 25 = 9 + p²
→ 25-9 = p²
→ 16 = p²
→ √{16} = p
→ p = 4
- Base = 3, Hypotenuse = 5, Perpendicular = 4
→ (5 sin A+3 sec A-3 tan A)/(4 cot A+4 cosec A + 5 cos A)
→ (5 × 4/3+3 × 5/3 - 3 × 4/3)/(4 × 3/4 + 4 × 5/4 + 5 × 3/5)
→ (4 + 5 - 4)/(3 + 5 + 3)
→ 5/11
Hence,
The value of (5 sin A+3 sec A-3 tan A)/(4 cot A+4 cosec A + 5 cos A) is 5/11.
Answer:
As We know that cos A = ⅗.
→ cos A = B/H
→ Cos A = ⅗
By Using Pythagoras theorem, we can find the Perpendicular of the traingle using h² = b² + p² Formula.
→ 5² = 3² + p²
→ 25 = 9 + p²
→ 25-9 = p²
→ 16 = p²
→ √{16} = p
→ p = 4
Base = 3, Hypotenuse = 5, Perpendicular = 4
→ (5 sin A+3 sec A-3 tan A)/(4 cot A+4 cosec A + 5 cos A)
→ (5 × 4/3+3 × 5/3 - 3 × 4/3)/(4 × 3/4 + 4 × 5/4 + 5 × 3/5)
→ (4 + 5 - 4)/(3 + 5 + 3)
→ 5/11
Hence,
The value of (5 sin A+3 sec A-3 tan A)/(4 cot A+4 cosec A + 5 cos A) is 5/11.