Question

I need this done please
Graph a circle with center A( -3, -2) that passes through point B( 1, 1). Write the equation in standard form.

Answer 1

Let it passes through any other point having coordinates (x,y)

As the radius is always fixed

So, the distance from the centre of the two points will always remain constant

So, the distance from (-1,-1) from centre (-3,-2) is the same as the distance from (x,y)

By squaring both sides --

(x-(-3))^2 + (y-(-2))^2 = (-3+1)^2 + (-2+1)^2

(x+3)^2 + (y+2)^2 = (-2)^2 + (-1)^2

x^2 + 6x + 9 + y^2 + 4y + 4 = 4 + 1

x^2 + y^2 + 6x + 4y + 8 =0

This is your required equation

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