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Here is ur answer.........
let a tower is BC and the man is at a a point A so according to the quetion
AB =50m
angle BAC =60 degree
a triangle is formed named ABC
so,
we need to find length or height of tower named BC
tan 60 degree = perpendicular to the base/base of the triangle
root 3=BC/AB
root 3=BC/50
so,
50 root 3=BC
HENCE,
the height of the tower is 50root 3 that is 50*(3)^1/2
HOPE IT HELPS UH.....
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let a tower is BC and the man is at a a point A so according to the quetion
AB =50m
angle BAC =60 degree
a triangle is formed named ABC
so,
we need to find length or height of tower named BC
tan 60 degree = perpendicular to the base/base of the triangle
root 3=BC/AB
root 3=BC/50
so,
50 root 3=BC
HENCE,
the height of the tower is 50root 3 that is 50*(3)^1/2
HOPE IT HELPS UH.....
@@@@@@@@@@@@@@@@@@@@@@@@@@
@@@@@@@@@@@@@@@@@@@@@@@@@@
Anonymous:
SORRY I AM USING PC CANT SEND U PIC
Answered by
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I hope it will help you
See the solution in picture
The height of the tower is 86.6m
Please mark as a brainlist
See the solution in picture
The height of the tower is 86.6m
Please mark as a brainlist
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