Question

i need this solution..​

Answer 1

Answer:

Inner circumference = 75.42m

Area of path= 163. 43 m²

Step-by-step explanation:

2 x 22 x (x+2) = 88

7

x + 2 = 88 x 7 = 14

22 x 2

x= 12m is the inner radius

Inner circumference,

2 x 22 x 12 = 75.42

7

75.42 m is the inner circumference.

Area of the path,

22 x (14²- 12²)= 22 x 52 = 163.43 m² approx

7 7

Answer 2

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GIVEN

Circular path is = 2 m wide

It has been given that 88m is the circumference of outer circle

TO FIND

Inner circumstances of the circular path = ?

And the area of the path = ¿

NOW

We know the formula of circumstances of circle .

$\boxed {=>2πr}$

Let R be radius of outer circle and r be radius of inner circle.

$:⟹ 2 × \frac{22}{7} × R = 88$

So, outer circumference of path

$~~~~~~~~~~~~~~~$

$:⟹ 2 × \frac{22}{7} × R = 88$

$~~~~~~~~~~~~~~~$

$:⟹ R = \frac{88}{2 × \frac{22}{7}}$

$~~~~~~~~~~~~~~~$

$:⟹ R = \frac{7 × 88}{2 × 22}$

$~~~~~~~~~~~~~~~$

$:⟹ R = \frac{616}{44}$

$~~~~~~~~~~~~~~~$

${:⟹ R = \frac{\cancel 616^{14}}{\cancel 44_{1}}}$

$~~~~~~~~~~~~~~~$

$:⟹ R = 14m$

So R be radius of outer circle. So the value of R is = 14m

It is given that circular path is 2 m wide.

So, radius of inner circle r

$~~~~~~~~~~~~~~~~ r = R - 2$

$~~~~~~~~~~~~~~~~ r = 7 - 2$

$~~~~~~~~~~~~~~~~ r = 5m$

So the inner circle r = 5m

So, inner circumference of path ;

We know the formula of circumstances of circle .

$\boxed {=> 2πr}$

$~~~~~~~~~~~~~~~$

$:⟹ 2 × \frac{22}{7} × 5m$

$~~~~~~~~~~~~~~~$

$:⟹ 10 × \frac{22}{7}$

$~~~~~~~~~~~~~~~$

$:⟹ 10 × \frac{22}{7}$

$~~~~~~~~~~~~~~~$

$:⟹ 31.42 m$

Therefore ;

$\boxed{Area \:of \:the \:path = \:area \:of \:outer \:circle - \:area \:of \:inner \:circle}$

We know the formula ;

$\boxed {π (R² - r² )}$

$:⟹ \frac{22}{7} (7² - 5²)$

$:⟹ \frac{22}{7} (49 - 25)$

$:⟹ \frac{22}{7} (24)$

$:⟹ 75.43 m²$

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• Inner circle radius - 5m
• Outer circle radius - 7m
• Area of path - 75.43m²

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