Question

I need to demostrate this Pythagorean identities

cosA/1+sinA + TanA = SecA

SenA-2sin3A / 2cos3A - cosA = Tan A

1+ sin A / 1 - sin A - 1-Sin A / 1+ Sin A = 4 Tan A sec A

Answer 1

↪Answer↩

Given : cosA/1 + sinA + tanA

= $\ \textgreater \ \frac{cosA}{1 + sinA} + \frac{sinA}{cosA}$

= $\ \textgreater \ \frac{cos^2A + sinA(1 + sinA)}{(1 + sinA)(cosA)}$

= $\ \textgreater \ \frac{cos^2A + sinA + sin^2A}{(1 + sinA)(cosA)}$

=$\ \textgreater \ \frac{1 + sinA}{(1 + sinA)(cosA)}$

= $\ \textgreater \ \frac{1}{cosA}$

SecA.

Answer 2

Answer:

check the attachment_______$❣️$