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In this question,a man whose weight is 90 kg standing on his feet(legs) on a ground(floor).The total are of contact of his feet(legs) on the ground(floor) is 0.006 m2.
(a)How much force(pressure) is taken by him on the ground(floor).
(b)What force(pressure) will be taken to the ground(floor) if he stands on one foot(legs).
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the weight of the man
so according to the solution,
f=force
F-mg=90 kilograms ×10 m s^-2 =900Newton
so to find out the pressure we have to apply the formula which is Pressure=Force/Area
=900N/0.036msquare=25000pascal
So according to the 2nd
force/areaof 1 foot
=900N/0.018msquare
=50000m^2
HOPE YOU LIKE IT
so according to the solution,
f=force
F-mg=90 kilograms ×10 m s^-2 =900Newton
so to find out the pressure we have to apply the formula which is Pressure=Force/Area
=900N/0.036msquare=25000pascal
So according to the 2nd
force/areaof 1 foot
=900N/0.018msquare
=50000m^2
HOPE YOU LIKE IT
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