Question

I need to know where
$\frac{bd}{qs}$
Has gone in theorem.... Below =therefore using Aa similarity criterion, we have,
Triangle ABD ~ PQS ​

Answer 1

Answer:

It's has been given that,

AB/PQ = BD/QS = AD/PS

As all three ratios is equal.

So, we can write any 2 pairs of equality.

Therefore,

AB/PQ = AD/PS

Hope you can understand it.

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