Question

I need ur help guzzzz !!!!!!!! Pls answer me it's urgent i mark brainliest ans. Who answer me first!!!!!!!!

Answer 1

take x as the common variable between the ratios and it is equal to 56.
Equate and solve it and you will get the answer as 15

Answer 2

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First method-

Water content in the original mixture =56×(27)=56×(27) =16=16 litres

Let xx litre of water be added to get the required ratio

16+x56+x=54+516+x56+x=54+5

144+9x144+9x =280+5x=280+5x

4x=1364x=136

x=34x=34 litres

Second method-

Initially the mixture is 7 parts. The final mixture can be understood of 9 parts, although
the parts will become different size. 

Concentration of milk at start is , and concentration of milk wanted is .

Simple two-part mixture problem. 

Let x be how many parts milk to add to the start mixture.
.Now, see the attachment-
Solve for x, the liters of milk to add.

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