I need your help. Steps please. Thank you
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mimansh:
what is written in the beginning
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divide(x+2)^1/2 from d denominator and (x-2)^1/2 from the numerator.
write x^2-3x as x(x-2)-x. now u will get x((x-2)^1/2) and another term (x-2)/((x-2)^1/2) simplify and dn put the value x=2
if u still face problems ask where. happy to help! :)
write x^2-3x as x(x-2)-x. now u will get x((x-2)^1/2) and another term (x-2)/((x-2)^1/2) simplify and dn put the value x=2
if u still face problems ask where. happy to help! :)
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