Math, asked by balaraju85010, 1 year ago

I NEEDED ANSWER PLZ​

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Answers

Answered by ItSdHrUvSiNgH
3

Step-by-step explanation:

p(x) =  \sqrt{2}  {x}^{3}  - 3 {x}^{2}  + 4 \sqrt{2} x - 6 \\ p( \sqrt{2} ) =  \sqrt{2}  {( \sqrt{2} )}^{3}  - 3 {( \sqrt{2} )}^{2}  + 4 \sqrt{2} ( \sqrt{2} ) - 6 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 4 - 6 + 8 - 6 \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = 0

Answered by KokilaAbhishek
0

Answer:

Hey mate ,the value of p(√2) is 0

Step-by-step explanation:

p(√2)=√2*(√2)^3-3*(√2)^2+4√2*√2-6

= √2*2√2-3*2+8-6

=4-6+2

=6-6=0

Hope it helps you................

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