I needed the answer to this.... thanks in advance....
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when the semicircular sheet of paper is bent into form a conical cup then the radius of the semicircle become the slant height of the cone. so the radius = slant height
=>radius=diameter/2=28/2=14cm
=>radius=slant height = 14cm
=>circumference of the semicircle=πr=22/7 * 14 =44cm
we know that,
=>circumference of semicircle= circumference of the cone
=>44=2πR
=>44=2*22/7 * R
=>R=7cm
we know that,
l²=R²+h²
=>l²-r²=h²
=>14²-7²=h²
=>196-49=h²
=>147=h²
=>h=√147=7√3cm
depth of the cone=7√3 cm
capacity of the cone= volume of the cone
=1/3 πR²h
=1/3 * 22/7 * 7² *7√3
=22*7*7/√3
=622.4cm³
HOPE IT IS HELPFUL
=>radius=diameter/2=28/2=14cm
=>radius=slant height = 14cm
=>circumference of the semicircle=πr=22/7 * 14 =44cm
we know that,
=>circumference of semicircle= circumference of the cone
=>44=2πR
=>44=2*22/7 * R
=>R=7cm
we know that,
l²=R²+h²
=>l²-r²=h²
=>14²-7²=h²
=>196-49=h²
=>147=h²
=>h=√147=7√3cm
depth of the cone=7√3 cm
capacity of the cone= volume of the cone
=1/3 πR²h
=1/3 * 22/7 * 7² *7√3
=22*7*7/√3
=622.4cm³
HOPE IT IS HELPFUL
nikki1231:
pls mark it as brainliest
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