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In ∆ADB and ∆CDB
Angle ADB = Angle BDC ( 90 °)
AB = BC ( Given)
Angle A= Angle C ( opp. angles to equal sides )
therefore, ∆ADB is congruent to ∆CDB
BY CPCT
AD = DC
so,BD bisects AC
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Answer:
True.
Step-by-step explanation:
please mark me as brainliest.
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